यदि $\mathop A\limits^ \to = 4\hat i - 3\hat j$ तथा $\mathop B\limits^ \to = 6\hat i + 8\hat j$ तो $\mathop A\limits^ \to \, + \mathop B\limits^ \to $ का परिमाण तथा दिशा होगी
यदि $\mathop A\limits^ \to = 4\hat i - 3\hat j$ तथा $\mathop B\limits^ \to = 6\hat i + 8\hat j$ तो $\mathop A\limits^ \to \, + \mathop B\limits^ \to $ का परिमाण तथा दिशा होगी
$5,\,{\tan ^{ - 1}}(3/4)$
$5\sqrt 5 ,{\tan ^{ - 1}}(1/2)$
$10,\,{\tan ^{ - 1}}(5)$
$25,\,{\tan ^{ - 1}}(3/4)$
यदि $\mathop A\limits^ \to = 4\hat i - 3\hat j$ तथा $\mathop B\limits^ \to = 6\hat i + 8\hat j$ तो $\mathop A\limits^ \to \, + \mathop B\limits^ \to $ का परिमाण तथा दिशा होगी
$\mathop A\limits^ \to + \mathop B\limits^ \to = 4\hat i - 3\hat j + 6\hat i + 8\hat j\,\, = 10\hat i + 5\hat j$
$|\mathop A\limits^ \to + \mathop B\limits^ \to |\, = \,\sqrt {{{(10)}^2} + {{(5)}^2}} $ $ = \,5\sqrt 5 $
$\tan \theta = \frac{5}{{10}} = \frac{1}{2}$ $ \Rightarrow $$\theta = {\tan ^{ - 1}}\left( {\frac{1}{2}} \right)$