यदि $\mathop A\limits^ \to = 2\hat i + 4\hat j - 5\hat k$ तो सदिश $\mathop A\limits^ \to $ की दिक्कोज्यायें हैं
$\frac{2}{{\sqrt {45} }},\frac{4}{{\sqrt {45} }}$ तथा $\,\frac{{ - \,{\rm{5}}}}{{\sqrt {{\rm{45}}} }}$
$\frac{1}{{\sqrt {45} }},\frac{2}{{\sqrt {45} }}$ तथा $\frac{{\rm{3}}}{{\sqrt {{\rm{45}}} }}$
$\frac{4}{{\sqrt {45} }},\,0\,{\rm{}}\,\frac{{\rm{4}}}{{\sqrt {45} }}$ तथा $\frac{{\rm{4}}}{{\sqrt {45} }}$
$\frac{3}{{\sqrt {45} }},\frac{2}{{\sqrt {45} }}\,{\rm{}}\,\frac{{\rm{5}}}{{\sqrt {{\rm{45}}} }}$ तथा $\frac{{\rm{5}}}{{\sqrt {{\rm{45}}} }}$
यदि $\mathop A\limits^ \to = 2\hat i + 4\hat j - 5\hat k$ तो सदिश $\mathop A\limits^ \to $ की दिक्कोज्यायें हैं
$\mathop A\limits^ \to = 2\hat i + 4\hat j - 5\hat k$
$|\overrightarrow A |\, = \sqrt {{{(2)}^2} + {{(4)}^2} + {{( - 5)}^2}} \, = \,\sqrt {45} $
$\cos \alpha = \frac{2}{{\sqrt {45} }},\,\,\,\,\,\cos \beta = \frac{4}{{\sqrt {45} }},\,\,\,\,\cos \gamma = \frac{{ - 5}}{{\sqrt {45} }}$
$|\overrightarrow A |\, = \sqrt {{{(2)}^2} + {{(4)}^2} + {{( - 5)}^2}} \, = \,\sqrt {45} $
$\cos \alpha = \frac{2}{{\sqrt {45} }},\,\,\,\,\,\cos \beta = \frac{4}{{\sqrt {45} }},\,\,\,\,\cos \gamma = \frac{{ - 5}}{{\sqrt {45} }}$
Other Language