किसी मीनार के शीर्ष से दो पत्थर जिनके द्रव

first stone thrown straight up with velocity $u$ upward and gravitation acceleration acts downwards.

so first particle goes up to some height when its velocity becomes zero and then this particle gets free fall. now when the particle goes down at level of top of tower it velocity becomes $u$ downward and gravitation acceleration also in downward direction.

by using newtons law of motion. for first particle

$v^2=u^2+2$ as $\quad(a=g ; s=h$ height of tower)

$v_1^2=u^2+2 g h$

same as for second particle

initial velocity is u downward and $g$ downward

$v^2=u^2+2$ as $\quad(a=g ; \quad s=h$ height of tower $)$

$v_2^2=u^2+2 g h$

So both the stones have same speed at the ground level hence option $C$ is correct