સદિશો $ \overrightarrow A = 3\hat i - 6\hat j + 2\hat k $ અને $ \overrightarrow B = 2\hat i + \hat j - 2\hat k $ બનતા ત્રિકોણનું ક્ષેત્રફળ કેટલું થશે?
$ \frac{5}{2}\sqrt {17} $ sq.unit
$ \frac{2}{5}\sqrt {17} $ sq.unit
$ \frac{3}{5}\sqrt {17} $ sq.unit
$ \frac{5}{3}\sqrt {17} $ sq.unit
સદિશો $ \overrightarrow A = 3\hat i - 6\hat j + 2\hat k $ અને $ \overrightarrow B = 2\hat i + \hat j - 2\hat k $ બનતા ત્રિકોણનું ક્ષેત્રફળ કેટલું થશે?
Given $\overrightarrow {OA} = \overrightarrow a = 3\hat i - 6\hat j + 2\hat k$ and $\overrightarrow {OB} = \overrightarrow b = 2\hat i + \hat j - 2\hat k$
$\therefore \,\,\,(\overrightarrow a \times \overrightarrow b )\, $ $= \left| {\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\hat k}\\{\,3\,\,}&{ -6\,\,\,}&2\\{\,\,\,2\,\,\,}&{1\,\,}&{ - 2\,\,\,}\end{array}}\right|\,$ $ = (12 - 2)\hat i + (4 + 6)\hat j + (3 + 12)\hat k$ $ = 10\hat i + 10\hat j + 15\hat k$ $\Rightarrow \,\,|\overrightarrow a \times \overrightarrow b |\, = \,\sqrt {{{10}^2} + {{10}^2} + {{15}^2}} $
$ =\sqrt {425} $ $ = 5\sqrt {17} $
Area of $\Delta OAB = \frac{1}{2}|\overrightarrow a \times \overrightarrow b |\, =\frac{{5\sqrt {17} }}{2}\,$sq.unit.
Other Language