પાણીનો પંપ 100 kg ના પાણીને 5 sec માં 10m

Work output of engine $= mgh = $ $100 \times 10 \times 10 = {10^4}J$

Efficiency ($\eta$) = $\frac{{{\rm{output}}}}{{{\rm{input}}}}$

Input energy = $\frac{{{\rm{outupt}}}}{\eta }$

$ = \frac{{{{10}^4}}}{{60}} \times 100 = \frac{{{{10}^5}}}{6}J$

 Power = $\frac{{{\rm{input energy}}}}{{{\rm{time}}}}$= $\frac{{{{10}^5}/6}}{5} = \frac{{{{10}^5}}}{{30}} = 3.3\;kW$