એક પૈડું અચળ કોણીય પ્રવેગથી ભ્રમણ કરે છે.શ

Using relation $\theta = {\omega _0}t + \frac{1}{2}a{t^2}$

${\theta _1} = \frac{1}{2}(\alpha ){(2)^2} = 2\alpha $…$(i) $  (As ${\omega _0} = 0,t = 2\,\sec $)

Now using same equation for $t = 4 \,sec$, $\omega_0 = 0$

${\theta _1} + {\theta _2} = \frac{1}{2}\alpha {(4)^2} = 8\alpha $…$(ii)$

From $(i)$ and $(ii),$

${\theta _1} = 2\alpha $and${\theta _2} = 6\alpha $    $\frac{{{\theta _2}}}{{{\theta _1}}} = 3$