એક પદાર્થને h ઊંચાઇ પરથી મુકત કરતાં તે છેલ

Let $h$ distance is covered in $n$ sec

$ \Rightarrow h = \frac{1}{2}g{n^2}$…(i)

Distance covered in ${n^{th}}$sec$ = \frac{1}{2}g(2n - 1)$

$ \Rightarrow \frac{{9h}}{{25}} = \frac{g}{2}(2n - 1)$…(ii)

From $(i)$ and $(ii)$,

$h = 122.5\;m$