20 m લંબાઇ અને 1 m ઉંચાઇના ઢાળ પર 100 kg ન

$v = 7.2\frac{{km}}{h} = 7.2 \times \frac{5}{{18}} = 2\;m/s$

Slope is given $1$ in $20$   $\sin \theta = \frac{1}{{20}}$

When man and cycle moves up then component of weight opposes it motion i.e. $F = mg\sin \theta $

So power of the man $P = F \times v$

$ = mg\sin \theta \times v$

=$100 \times 9.8 \times \left( {\frac{1}{{20}}} \right) \times 2 = 98\;Watt$