0.5 kg ના દડાને 14 m/s ના વેગથી ઉપર તરફ ફે

If there is no air drag then maximum height

$H = \frac{{{u^2}}}{{2g}} = \frac{{14 \times 14}}{{2 \times 9.8}} = 10\,m$

But due to air drag ball reaches up to height $8m$ only.

So loss in energy $ = mg(10 - 8) = 0.5 \times 9.8 \times 2 = 9.8\,J$