$Y $ component of velocity is $20$ and $X$ component of velocity is $10$. The direction of motion of the body with the horizontal at this instant is
${\tan ^{ - 1}}(2)$
${\tan ^{ - 1}}(1/2)$
$45^°$
$0^°$
$Y $ component of velocity is $20$ and $X$ component of velocity is $10$. The direction of motion of the body with the horizontal at this instant is
${v_y} = 20$ and ${v_x} = 10$
$\therefore $ velocity $\vec v = 10\hat i + 20\hat j$
direction of velocity with $X$ axis
$\tan \theta = \frac{{{v_y}}}{{{v_x}}} = \frac{{20}}{{10}} = 2$
$\therefore $ $\theta = {\tan ^{ - 1}}(2)$
$\therefore $ velocity $\vec v = 10\hat i + 20\hat j$
direction of velocity with $X$ axis
$\tan \theta = \frac{{{v_y}}}{{{v_x}}} = \frac{{20}}{{10}} = 2$
$\therefore $ $\theta = {\tan ^{ - 1}}(2)$