When A⃗.B⃗ = - |A||B|, then

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When $\vec A.\vec B = - |A||B|,$ then

A

$\vec A$ and $\vec B$ are perpendicular to each other

B

$\vec A$ and $\vec B$ act in the same direction

C

$\vec A$ and $\vec B$ act in the opposite direction

D

$\vec A$ and $\vec B$ can act in any direction

When $\vec A.\vec B = - |A||B|,$ then

$\overrightarrow A .\overrightarrow B = AB\cos \theta $

In the problem $\overrightarrow A .\overrightarrow B = - AB$ i.e. $\cos \theta = - 1$

$\theta = 180^\circ $

i.e. $\overrightarrow A $ and $\overrightarrow B $ acts in the opposite direction.