Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be
Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be
$1.99 \times {10^{30}}\,kg$
$7.56 \times {10^{22}}\,kg$
$5.98 \times {10^{24}}\,kg$
$7.65 \times {10^{22}}\,kg$
Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be
${g_m} = \frac{{G{M_m}}}{{R_m^2}}$ and ${g_m} = \frac{{{g_e}}}{6} = \frac{{9.8}}{6}\;m/{s^2}$$ = 1.63\;m/{s^2}$
Substituting ${R_m} = 1.768 \times {10^6}m,$ ${g_m} = 1.63\;m/{s^2}$ and $G = 6.67 \times {10^{ - 11}}N{\rm{ - }}{m^2}/k{g^2}$
We get ${M_m} = 7.65 \times {10^{22}}kg$
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