Two springs have their force constant as ${k_1}$ and ${k_2}({k_1} > {k_2})$. When they are stretched by the same force
Two springs have their force constant as ${k_1}$ and ${k_2}({k_1} > {k_2})$. When they are stretched by the same force
No work is done in case of both the springs
Equal work is done in case of both the springs
More work is done in case of second spring
More work is done in case of first spring
Two springs have their force constant as ${k_1}$ and ${k_2}({k_1} > {k_2})$. When they are stretched by the same force
$W = \frac{{{F^2}}}{{2k}}$
If both springs are stretched by same force then$W \propto \frac{1}{k}$
As ${k_1} > {k_2}$ therefore ${W_1} < {W_2}$
i.e. more work is done in case of second spring.