Two satellite $A$ and $B$, ratio of masses $3 : 1$ are in circular orbits of radii $r$ and $4r$. Then ratio of total mechanical energy of $ A$ to $B$ is
Two satellite $A$ and $B$, ratio of masses $3 : 1$ are in circular orbits of radii $r$ and $4r$. Then ratio of total mechanical energy of $ A$ to $B$ is
$1:3$
$3:1$
$3:4$
$12:1$
Two satellite $A$ and $B$, ratio of masses $3 : 1$ are in circular orbits of radii $r$ and $4r$. Then ratio of total mechanical energy of $ A$ to $B$ is
Total mechanical energy of satellite $E = \frac{{ - GMm}}{{2r}}$
$\frac{{{E_A}}}{{{E_B}}} = \frac{{{m_A}}}{{{m_B}}} \times \frac{{{r_B}}}{{{r_A}}}$
$=\frac{3}{1} \times \frac{{4r}}{r}$
$=\frac{{12}}{1}$
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