Two bodies of different masses ${m_a}$ and ${m_b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are
Two bodies of different masses ${m_a}$ and ${m_b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are
$a:b$
$b:a$
$\sqrt a :\sqrt b $
${a^2}:{b^2}$
Two bodies of different masses ${m_a}$ and ${m_b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are
$h = \frac{1}{2}g{t^2} \Rightarrow t = \sqrt {2h/g} $
${t_a} = \sqrt {\frac{{2a}}{g}} \,\,{\rm{and}}\;\,{t_b} = \sqrt {\frac{{2b}}{g}} \Rightarrow \frac{{{t_a}}}{{{t_b}}} = \sqrt {\frac{a}{b}} $
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