Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force $F$ applied on the upper string produces an acceleration of $2\,m/{s^2}$ in the upward direction in both the blocks. If $T$ and $T'$ be the tensions in the two parts of the string, then $T$ and $T'$
Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force $F$ applied on the upper string produces an acceleration of $2\,m/{s^2}$ in the upward direction in both the blocks. If $T$ and $T'$ be the tensions in the two parts of the string, then $T$ and $T'$
$T = 70.8N$ and $T' = 47.2N$
$T = 58.8N$ and $T' = 47.2N$
$T = 70.8N$ and $T' = 58.8N$
$T = 70.8N$ and $T' = 0$
Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force $F$ applied on the upper string produces an acceleration of $2\,m/{s^2}$ in the upward direction in both the blocks. If $T$ and $T'$ be the tensions in the two parts of the string, then $T$ and $T'$
$4a = T' - 4g$ .….(i)
$2a = T - T' - 2g$ .….(ii)
From (i) and (ii)
$6a=T-6g$
$ 12=T-6\times 9.8$
$T= 70.8\, N$
$T' = 47.2N$
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