Two balls of masses ${m_1}$ and ${m_2}$ are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass ${m_1}$ travels a distance ${s_1}$ and stops. If the coefficients of friction between the balls and ground are same, the mass ${m_2}$ stops after travelling the distance
Two balls of masses ${m_1}$ and ${m_2}$ are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass ${m_1}$ travels a distance ${s_1}$ and stops. If the coefficients of friction between the balls and ground are same, the mass ${m_2}$ stops after travelling the distance
${s_2} = \frac{{{m_1}}}{{{m_2}}}{s_1}$
${s_2} = \frac{{{m_2}}}{{{m_1}}}{s_1}$
${s_2} = \frac{{m_1^2}}{{m_2^2}}{s_1}$
${s_2} = \frac{{m_2^2}}{{m_1^2}}{s_1}$
Two balls of masses ${m_1}$ and ${m_2}$ are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass ${m_1}$ travels a distance ${s_1}$ and stops. If the coefficients of friction between the balls and ground are same, the mass ${m_2}$ stops after travelling the distance
We know that in the given condition $s \propto \frac{1}{{{m^2}}}$
$\therefore \frac{{{s_2}}}{{{s_1}}} = {\left( {\frac{{m{_1}}}{{{m_2}}}} \right)^2}$ $⇒$ ${s_2} = {\left( {\frac{{m_1^{}}}{{m_2^{}}}} \right)^2} \times {s_1}$