Two balls are dropped from heights $h$ and $2h$ respectively from the earth surface. The ratio of time of these balls to reach the earth is
$1:\sqrt 2 $
$\sqrt 2 $ $: 1$
$2:1$
$1:4$
Two balls are dropped from heights $h$ and $2h$ respectively from the earth surface. The ratio of time of these balls to reach the earth is
$t = \sqrt {\frac{{2h}}{g}} \Rightarrow \frac{{{t_1}}}{{{t_2}}} = \sqrt {\frac{{{h_1}}}{{{h_2}}}} = \sqrt {\frac{1}{2}} = \frac{1}{{\sqrt 2 }}$