The vector sum of two forces is perpendicular to their vector differences. In that case, the force
The vector sum of two forces is perpendicular to their vector differences. In that case, the force
Are equal to each other in magnitude
Are not equal to each other in magnitude
Cannot be predicted
Are equal to each other
The vector sum of two forces is perpendicular to their vector differences. In that case, the force
Let two vectors be $\overrightarrow A $ and $\overrightarrow B $ then
$(\overrightarrow A + \overrightarrow B ).(\overrightarrow A - \overrightarrow B ) = 0$
$\overrightarrow A \;.\;\overrightarrow A - \overrightarrow B \;.\;\overrightarrow B + \overrightarrow B \;.\;\overrightarrow A - \overrightarrow B \;.\;\overrightarrow B = 0$
${A^2} - {B^2} = 0$ $⇒$ ${A^2} = {B^2}$
$\therefore \;\;A = B$
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