The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ......... $hours$
$20$
$10$
$80$
$40$
The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ......... $hours$
${T_2} = {T_1}{\left( {\frac{{{R_2}}}{{{R_1}}}} \right)^{3/2}} = {T_1}{(4)^{3/2}} = 8{T_1} = 40\,hr$
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