The string of pendulum of length $l$ is displaced through ${90^o}$ from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is
The string of pendulum of length $l$ is displaced through ${90^o}$ from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is
$mg$
$3mg$
$5\,mg$
$6\,mg$
The string of pendulum of length $l$ is displaced through ${90^o}$ from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is
$T = mg + \frac{{m{v^2}}}{l}$ $ = mg + 2mg = 3mg$
where $v = \sqrt {2gl} $ from $\frac{1}{2}m{v^2} = mgl$
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