The $SI$ unit of magnetic permeability is
$Wb\;m ^{-2}\; A ^{-1}$
$Wb\;m ^{-1}\; A$
$Wb\;m\;A ^{-1}$
$Wb\;m ^{-1} \;A ^{-1}$
The $SI$ unit of magnetic permeability is
$B =\frac{\mu_{0}}{4 \pi} \frac{{idlsin}(\theta)}{ r ^{2}}$
Now by putting Sl units of all measurable quantities in above formula
$\Rightarrow \frac{ W b }{ m ^{2}}=$ $\frac{ \mu_{0}Am }{ m ^{2}}$
$\Rightarrow \mu_0 =\frac{ W b }{ A \cdot m }$