The resultant of the two vectors having magnitude $2$ and $3$ is $1$. What is their cross product
The resultant of the two vectors having magnitude $2$ and $3$ is $1$. What is their cross product
$6$
$3$
$1$
$0$
The resultant of the two vectors having magnitude $2$ and $3$ is $1$. What is their cross product
$\sqrt {{2^2} + {3^2} + 2 \times 2 \times 3 \times \cos \theta } = 1$
By solving we get $\theta = 180^\circ $
$⇒$ $\vec A \times \vec B = 0$