The resultant of P and Q is perpendicular

Your Ultimate Guide to JEE & NEET Question Solutions

The resultant of $\overrightarrow P $ and $\overrightarrow Q $ is perpendicular to $\overrightarrow P $. What is the angle between $\overrightarrow P $ and $\overrightarrow Q $

A

${\cos ^{ - 1}}(P/Q)$

B

${\cos ^{ - 1}}( - P/Q)$

C

${\sin ^{ - 1}}\,(P/Q)$

D

${\sin ^{ - 1}}\,( - P/Q)$

The resultant of $\overrightarrow P $ and $\overrightarrow Q $ is perpendicular to $\overrightarrow P $. What is the angle between $\overrightarrow P $ and $\overrightarrow Q $

$\tan 90^\circ = \frac{{Q\sin \theta }}{{P + Q\cos \theta }}$

$⇒$ $P + Q\cos \theta = 0$

$\cos \theta = \frac{{ - P}}{Q}$ 

$⇒$ $\theta = {\cos ^{ - 1}}\left( {\frac{{ - P}}{Q}} \right)$

Other Language

Popular Questions