The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is ($5.00 \pm 0.05$) Newton and weight in water is ($4.00 \pm 0.05$) Newton. Then the relative density along with the maximum permissible percentage error is
The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is ($5.00 \pm 0.05$) Newton and weight in water is ($4.00 \pm 0.05$) Newton. Then the relative density along with the maximum permissible percentage error is
$5.0 \pm 11\%$
$5.0 \pm 1\%$
$5.0 \pm 6\%$
$1.25 \pm 5\%$
The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is ($5.00 \pm 0.05$) Newton and weight in water is ($4.00 \pm 0.05$) Newton. Then the relative density along with the maximum permissible percentage error is
Weight in air $ = (5.00 \pm 0.05)\,N$
Weight in water$ = (4.00 \pm 0.05)\,N$
Loss of weight in water $ = (1.00 \pm 0.1)\,N$
Now relative density $ = \frac{{{\rm{weight}}\,{\rm{in}}\,{\rm{air }}}}{{{\rm{weight\, }}{\rm{loss\, in, water}}}}$
i.e. R . D$ = \frac{{5.00 \pm 0.05}}{{1.00 \pm 0.1}}$
Now relative density with max permissible error
$ = \frac{{5.00}}{{1.00}} \pm \left( {\frac{{0.05}}{{5.00}} + \frac{{0.1}}{{1.00}}} \right) \times 100$
$ = 5.0 \pm (1 + 10)\% $ $ = 5.0 \pm 11\% $
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