The relationship between the force $F$ and position $x$ of a body is as shown in figure. The work done in displacing the body from $x = 1$ m to $x = 5 $ m will be ........ $J$
$30 $
$15 $
$25$
$20$
The relationship between the force $F$ and position $x$ of a body is as shown in figure. The work done in displacing the body from $x = 1$ m to $x = 5 $ m will be ........ $J$
Work done $=$ area under $F-x $ graph
$=$ area of rectangle $ ABCD$ + area of rectangle $LCEF$
$+$ area of rectangle $ GFIH$ + area of triangle $IJK $
$ = (2 - 1) \times (10 - 0) + (3 - 2)(5 - 0) + (4 - 3)( - 5 - 0)$
$ + \frac{1}{2}(5 - 4)(10 - 0)$$ = 15\,\,J$