The relation $3t = \sqrt {3x} + 6$ describes the displacement of a particle in one direction where $x$ is in metres and $t$ in sec. The displacement, when velocity is zero, is.........$metres$
The relation $3t = \sqrt {3x} + 6$ describes the displacement of a particle in one direction where $x$ is in metres and $t$ in sec. The displacement, when velocity is zero, is.........$metres$
$24$
$12$
$5$
$0$
The relation $3t = \sqrt {3x} + 6$ describes the displacement of a particle in one direction where $x$ is in metres and $t$ in sec. The displacement, when velocity is zero, is.........$metres$
$3t = \sqrt {3x} + 6 \Rightarrow 3x = {(3t - 6)^2}$
$ \Rightarrow x = 3{t^2} - 12t + 12$
$v = \frac{{dx}}{{dt}} = 6t - 12$, for $v = 0,\;t = 2\sec $
$x = 3{(2)^2} - 12 \times 2 + 12 = 0$
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