The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration $‘a’$ is $3 : 2$. The value of $‘a’$ is ($g-$Acceleration due to gravity of the earth)
The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration $‘a’$ is $3 : 2$. The value of $‘a’$ is ($g-$Acceleration due to gravity of the earth)
$\frac{3}{2}g$
$\frac{g}{3}$
$\frac{2}{3}g$
$g$
The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration $‘a’$ is $3 : 2$. The value of $‘a’$ is ($g-$Acceleration due to gravity of the earth)
$\frac{{mg}}{{m(g - a)}} = \frac{3}{2}$
$⇒$ $a = g/3$
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