The ratio of the $K.E.$ required to be given to the satellite to escape earth's gravitational field to the $K.E.$ required to be given so that the satellite moves in a circular orbit just above earth atmosphere is
$1$
$2$
$\frac{1}{2}$
$\infty $
The ratio of the $K.E.$ required to be given to the satellite to escape earth's gravitational field to the $K.E.$ required to be given so that the satellite moves in a circular orbit just above earth atmosphere is
$K.E.$ required for satellite to escape from earth's gravitational field
$\frac{1}{2}mv_e^2 = \frac{1}{2}m{\left( {\sqrt {\frac{{2GM}}{R}} } \right)^2} = \frac{{GMm}}{R}$
$K.E.$ required for satellite to move in circular orbit
$\frac{1}{2}mv_0^2 = \frac{1}{2}m{\left( {\sqrt {\frac{{GM}}{R}} } \right)^2} = \frac{{GMm}}{{2R}}$
The ratio between these two energies $= 2$
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