The range of a particle when launched at an angle of ${15^o}$ with the horizontal is $1.5 \,km$. What is the range of the projectile when launched at an angle of ${45^o}$ to the horizontal ........ $km$
The range of a particle when launched at an angle of ${15^o}$ with the horizontal is $1.5 \,km$. What is the range of the projectile when launched at an angle of ${45^o}$ to the horizontal ........ $km$
$1.5 $
$3.0$
$6.0$
$0.75$
The range of a particle when launched at an angle of ${15^o}$ with the horizontal is $1.5 \,km$. What is the range of the projectile when launched at an angle of ${45^o}$ to the horizontal ........ $km$
${R_{15^\circ }} = \frac{{{u^2}\sin (2 \times 15^\circ )}}{g}$$ = \frac{{{u^2}}}{{2g}} = 1.5\,km$
${R_{45^\circ }} = \frac{{{u^2}\sin (2 \times 45^\circ )}}{g} = \frac{{{u^2}}}{g} = 1.5 \times 2 = 3\,km$
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