The position vector of a particle is $\vec r = (a\cos \omega t)\hat i + (a\sin \omega t)\hat j$. The velocity of the particle is
Parallel to the position vector
Perpendicular to the position vector
Directed towards the origin
Directed away from the origin
The position vector of a particle is $\vec r = (a\cos \omega t)\hat i + (a\sin \omega t)\hat j$. The velocity of the particle is
$\vec r = (a\cos \omega \,t)\hat i + (a\sin \omega \,t)\hat j$
$\vec v = \frac{{d\vec r}}{{dt}} = - a\omega \sin \omega \,t\,\hat i + a\omega \cos \omega \,t\,\hat j$
As $\vec r.\vec v = 0$ therefore velocity of the particle is perpendicular to the position vector.
$\vec v = \frac{{d\vec r}}{{dt}} = - a\omega \sin \omega \,t\,\hat i + a\omega \cos \omega \,t\,\hat j$
As $\vec r.\vec v = 0$ therefore velocity of the particle is perpendicular to the position vector.
Other Language