The orbital speed of an artificial satellite very close to the surface of the earth is ${V_o}$. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is
The orbital speed of an artificial satellite very close to the surface of the earth is ${V_o}$. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is
$4\,{V_o}$
$2\,{V_o}$
$0.5\,{V_o}$
$4\,{V_o}$
The orbital speed of an artificial satellite very close to the surface of the earth is ${V_o}$. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is
$v \propto \frac{1}{{\sqrt r }},$ If $r = R$ then $v = {V_0}$
If $r = R + h = R + 3R = 4R $ then $v = \frac{{{V_0}}}{2} = 0.5{V_0}$
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