The maximum and minimum distances of a comet from the sun are $8 \times {10^{12}}\,m$ and $1.6 \times {10^{12}}\,m$. If its velocity when nearest to the sun is $60\, m/s$, what will be its velocity in $m/s$ when it is farthest
The maximum and minimum distances of a comet from the sun are $8 \times {10^{12}}\,m$ and $1.6 \times {10^{12}}\,m$. If its velocity when nearest to the sun is $60\, m/s$, what will be its velocity in $m/s$ when it is farthest
$12$
$60$
$112$
$6$
The maximum and minimum distances of a comet from the sun are $8 \times {10^{12}}\,m$ and $1.6 \times {10^{12}}\,m$. If its velocity when nearest to the sun is $60\, m/s$, what will be its velocity in $m/s$ when it is farthest
By conservation of angular momentum $mvr =$ constant
${v_{\min }} \times {r_{\max }} = {v_{\max }} \times {r_{\min }}$
${v_{\min }} = \frac{{60 \times 1.6 \times {{10}^{12}}}}{{8 \times {{10}^{12}}}} = \frac{{60}}{5} = 12\,m/s$
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