The mass of the earth is $81$ times that of the moon and the radius of the earth is $3.5$ times that of the moon. The ratio of the acceleration due to gravity at the surface of the moon to that at the surface of the earth is
$0.15$
$0.04$
$1$
$6$
The mass of the earth is $81$ times that of the moon and the radius of the earth is $3.5$ times that of the moon. The ratio of the acceleration due to gravity at the surface of the moon to that at the surface of the earth is
$g = \frac{{GM}}{{{R^2}}}$ (Given ${M_e} = 81{M_m},\,\,\,{R_e} = 3.5{R_m})$
Substituting the above values, $\frac{{{g_m}}}{{{g_e}}} = 0.15$
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