The magnitude of a given vector with end points $ (4, -4, 0)$ and $(-2, -2, 0)$ must be
$6$
$5\sqrt 2 $
$4$
$2\sqrt {10} $
The magnitude of a given vector with end points $ (4, -4, 0)$ and $(-2, -2, 0)$ must be
$\vec r = {\vec r_2} - {\vec r_1} = ( - 2\hat i - 2\hat j + 0\hat k) - (4\hat i - 4\hat j + 0\hat k)$
$⇒$ $\vec r = - 6\hat i + 2\hat j + 0\hat k$
$\therefore |\vec r| = \sqrt {{{( - 6)}^2} + {{(2)}^2} + {0^2}} = \sqrt {36 + 4} = \sqrt {40} = 2\sqrt {10} $
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