The length of second's hand in a watch is $1 \,cm.$ The change in velocity of its tip in $15\, seconds$ is
The length of second's hand in a watch is $1 \,cm.$ The change in velocity of its tip in $15\, seconds$ is
Zero
$\frac{\pi }{{30\sqrt 2 }}cm/\sec $
$\frac{\pi }{{30}}cm/\sec $
$\frac{{\pi \sqrt 2 }}{{30}}cm/\sec $
The length of second's hand in a watch is $1 \,cm.$ The change in velocity of its tip in $15\, seconds$ is
In $15\, second's$ hand rotate through $90°$.
Change in velocity $\left| {\overrightarrow {\Delta v} } \right| = 2v\sin (\theta /2)$
$ = 2(r\omega )\sin (90^\circ /2)$$ = 2 \times 1 \times \frac{{2\pi }}{T} \times \frac{1}{{\sqrt 2 }}$
$ = \frac{{4\pi }}{{60\sqrt 2 }} = \frac{{\pi \sqrt 2 }}{{30}}\frac{{cm}}{{\sec }}$ [As $T = 60 \,sec$]
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