The horizontal range of a projectile is $4\sqrt 3 $ times its maximum height. Its angle of projection will be ......... $^o$
The horizontal range of a projectile is $4\sqrt 3 $ times its maximum height. Its angle of projection will be ......... $^o$
${45}$
${60}$
${90}$
${30}$
The horizontal range of a projectile is $4\sqrt 3 $ times its maximum height. Its angle of projection will be ......... $^o$
$R = 4H\cot \theta ,$
If $R =4\sqrt 3 H$ then $\cot \theta = \sqrt 3 $
$⇒$ $\theta = 30^\circ $