The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5{t^2})$ meter and $x = 6t\, meter$, where $t$ is in second. The velocity with which the projectile is projected is ......... $m/sec$.
The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5{t^2})$ meter and $x = 6t\, meter$, where $t$ is in second. The velocity with which the projectile is projected is ......... $m/sec$.
$8$
$6$
$10$
Not obtainable from the data
The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5{t^2})$ meter and $x = 6t\, meter$, where $t$ is in second. The velocity with which the projectile is projected is ......... $m/sec$.
${v_y} = \frac{{dy}}{{dt}} = 8 - 10t$, ${v_x} = \frac{{dx}}{{dt}} = 6$
at the time of projection i.e. ${v_y} = \frac{{dy}}{{dt}} = 8$and ${v_x} = 6$
$\therefore v = \sqrt {v_x^2 + v_y^2} = \sqrt {{6^2} + {8^2}} = 10\;m/s$
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