The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)
$8 \,R$
$9 \,R$
$10 \,R$
$20 \,R$
The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)
$\frac{{g'}}{g} = \,{\left( {\frac{R}{{R + h}}} \right)^2} \Rightarrow \frac{1}{{100}}\, = \,{\left( {\frac{R}{{R + h}}} \right)^2} \Rightarrow h = 9R$
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