The height of the point vertically above t

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The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)

A

$8 \,R$

B

$9 \,R$

C

$10 \,R$

D

$20 \,R$

The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)

$\frac{{g'}}{g} = \,{\left( {\frac{R}{{R + h}}} \right)^2} \Rightarrow \frac{1}{{100}}\, = \,{\left( {\frac{R}{{R + h}}} \right)^2} \Rightarrow h = 9R$