The greatest height to which a man can throw a stone is $h$. The greatest distance to which he can throw it, will be
$h/2$
$h$
$2h$
$3h$
The greatest height to which a man can throw a stone is $h$. The greatest distance to which he can throw it, will be
For greatest height $\theta = 90^°$
${H_{\max }} = \frac{{{u^2}{{\sin }^2}(90^\circ )}}{{2g}} = \frac{{{u^2}}}{{2g}} = h$ (given)
${R_{\max }} = \frac{{{u^2}{{\sin }^2}2(45^\circ )}}{g} = \frac{{{u^2}}}{g} = 2h$
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