The gravitational potential energy of a body of mass $‘m’$ at the earth’s surface $ - mg{R_e}$. Its gravitational potential energy at a height ${R_e}$ from the earth’s surface will be (Here ${R_e}$ is the radius of the earth)
The gravitational potential energy of a body of mass $‘m’$ at the earth’s surface $ - mg{R_e}$. Its gravitational potential energy at a height ${R_e}$ from the earth’s surface will be (Here ${R_e}$ is the radius of the earth)
$ - 2\,mg{R_e}$
$2\,mg{R_e}$
$\frac{1}{2}mg{R_e}$
$ - \frac{1}{2}mg{R_e}$
The gravitational potential energy of a body of mass $‘m’$ at the earth’s surface $ - mg{R_e}$. Its gravitational potential energy at a height ${R_e}$ from the earth’s surface will be (Here ${R_e}$ is the radius of the earth)
$\Delta U = {U_2} - {U_1} = \frac{{mgh}}{{1 + \frac{h}{{{R_e}}}}} = \frac{{mg{R_e}}}{{1 + \frac{{{R_e}}}{{{R_e}}}}} = \frac{{mg{R_e}}}{2}$
$\, \Rightarrow \,{U_2} - ( - mg{R_e}) = \frac{{mg{R_e}}}{2}$ $⇒$ ${U_2} = - \frac{1}{2}mg{R_e}$
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