The graph between the resistive force $ F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25\, kg$ and initial velocity is $2\, m/s$. When the distance covered by the body is $4m$, its kinetic energy would be .............. $\mathrm{J}$
The graph between the resistive force $ F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25\, kg$ and initial velocity is $2\, m/s$. When the distance covered by the body is $4m$, its kinetic energy would be .............. $\mathrm{J}$
$50$
$40 $
$20$
$10$
The graph between the resistive force $ F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25\, kg$ and initial velocity is $2\, m/s$. When the distance covered by the body is $4m$, its kinetic energy would be .............. $\mathrm{J}$
Initial K.E. of the body = $\frac{1}{2}m{v^2} = \frac{1}{2} \times 25 \times 4 = 50\,\,J$
Work done against resistive force
= Area between F-x graph
= $\frac{1}{2} \times 4 \times 20 = 40J$
Final K.E. = Initial K.E. -Work done against resistive force
=$50 - 40 = 10\,\,J$
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