The force constant of a wire is k nbsp;

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The force constant of a wire is $k$ and that of another wire is $2k.$ When both the wires are stretched through same distance, then the work done

${W_2} = 2W_1^2$

${W_2} = 2{W_1}$

${W_2} = {W_1}$

${W_2} = 0.5{W_1}$

The force constant of a wire is $k$ and that of another wire is $2k.$ When both the wires are stretched through same distance, then the work done

$W = \frac{1}{2}k{x^2}$
If both wires are stretched through same distance then $W \propto k$. As ${k_2} = 2{k_1}$ so ${W_2} = 2{W_1}$

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