The escape velocity of an object from the

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The escape velocity of an object from the earth depends upon the mass of the earth $(M)$, its mean density $(\rho )$, its radius $(R)$ and the gravitational constant $(G)$. Thus the formula for escape velocity is

A

$v = R\sqrt {\frac{{8\pi }}{3}G\rho } $

B

$v = M\sqrt {\frac{{8\pi }}{3}GR} $

C

$v = \sqrt {2GMR} $

D

$v = \sqrt {\frac{{2GM}}{{{R^2}}}} $

The escape velocity of an object from the earth depends upon the mass of the earth $(M)$, its mean density $(\rho )$, its radius $(R)$ and the gravitational constant $(G)$. Thus the formula for escape velocity is

$\frac{-G M m}{R}+\frac{1}{2} m v^{2}=0$

$v=\sqrt{\frac{2 G M}{R}}$

$M=e \times \frac{4}{3} \pi R^{3}$

$v=\sqrt{\frac{2 G}{R} \times e \times \frac{4}{3} \pi R^{3}}$

$v=R \sqrt{\frac{8}{3} G \rho}$