The escape velocity of a planet having mass $6$ times and radius $2$ times as that of earth is
The escape velocity of a planet having mass $6$ times and radius $2$ times as that of earth is
$\sqrt 3 \,{V_e}$
$3\,{V_e}$
$\sqrt 2 \,{V_e}$
$2\,{V_e}$
The escape velocity of a planet having mass $6$ times and radius $2$ times as that of earth is
$\frac{{{v_p}}}{{{v_e}}} = \sqrt {\frac{{{M_p}}}{{{M_e}}} \times \frac{{{R_e}}}{{{R_p}}}} = \sqrt {6 \times \frac{1}{2}} = \sqrt 3 $
$\therefore \,\,\,{v_p} = \sqrt {3\,} {v_e}$
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