The escape velocity from the surface of earth is ${V_e}$. The escape velocity from the surface of a planet whose mass and radius are $3$ times those of the earth will be
The escape velocity from the surface of earth is ${V_e}$. The escape velocity from the surface of a planet whose mass and radius are $3$ times those of the earth will be
${V_e}$
$3{V_e}$
$9{V_e}$
$27{V_e}$
The escape velocity from the surface of earth is ${V_e}$. The escape velocity from the surface of a planet whose mass and radius are $3$ times those of the earth will be
${v_e} = \sqrt {\frac{{2GM}}{R}} $
${v_e} \propto \sqrt {\frac{M}{R}} $
If mass and radius of the planet are three times than that of earth then escape velocity will be same.
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