The earth (mass $ = 6 \times {10^{24}}\,kg)$) revolves round the sun with angular velocity $2 \times {10^{ - 7}}\,rad/s$ in a circular orbit of radius $1.5 \times {10^8}\,km$. The force exerted by the sun on the earth in newtons, is
The earth (mass $ = 6 \times {10^{24}}\,kg)$) revolves round the sun with angular velocity $2 \times {10^{ - 7}}\,rad/s$ in a circular orbit of radius $1.5 \times {10^8}\,km$. The force exerted by the sun on the earth in newtons, is
$18 \times {10^{25}}$
Zero
$27 \times {10^{39}}$
$36 \times {10^{21}}$
The earth (mass $ = 6 \times {10^{24}}\,kg)$) revolves round the sun with angular velocity $2 \times {10^{ - 7}}\,rad/s$ in a circular orbit of radius $1.5 \times {10^8}\,km$. The force exerted by the sun on the earth in newtons, is
$m = 6 \times {10^{24}}kg,$ $\omega = 2 \times {10^{ - 7}}rad/s,$ $R = 1.5 \times {10^{11}}m$
The force exerted by the sun on the earth $F = m{\omega ^2}R$
By substituting the value we can get, $F = 36 \times {10^{21}}N$
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