The driver of a car travelling at velocity $v$ suddenly see a broad wall in front of him at a distance $d$. He should
The driver of a car travelling at velocity $v$ suddenly see a broad wall in front of him at a distance $d$. He should
Brake sharply
Turn sharply
$(a)$ and $(b)$ both
None of the above
The driver of a car travelling at velocity $v$ suddenly see a broad wall in front of him at a distance $d$. He should
When driver applies brakes and the car covers distance $x$ before coming to rest, under the effect of retarding force $F$
then $\frac{1}{2}m{v^2} = Fx$
$⇒$ $x = \frac{{m{v^2}}}{{2F}}$
But when he takes turn then $\frac{{m{v^2}}}{r} = F$
$⇒$ $r = \frac{{m{v^2}}}{F}$
It is clear that $x = r/2$
i.e. by the same retarding force the car can be stopped in a less distance if the driver apply breaks. This retarding force is actually a friction force.
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