The distance travelled by a particle is proportional to the squares of time, then the particle travels with
The distance travelled by a particle is proportional to the squares of time, then the particle travels with
Uniform acceleration
Uniform velocity
Increasing acceleration
Decreasing velocity
The distance travelled by a particle is proportional to the squares of time, then the particle travels with
$s \propto {t^2}$ (given)
$\therefore s = K{t^2}$
Acceleration $a = \frac{{{d^s}s}}{{d{t^2}}} = 2k$ (constant)
It means the particle travels with uniform acceleration.