The diameters of two planets are in the ra

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The diameters of two planets are in the ratio $4 : 1$ and their mean densities in the ratio $1 : 2$. The acceleration due to gravity on the planets will be in ratio

A

$1:2$

B

$2:3$

C

$2:1$

D

$4:1$

The diameters of two planets are in the ratio $4 : 1$ and their mean densities in the ratio $1 : 2$. The acceleration due to gravity on the planets will be in ratio

$g = \frac{4}{3}G\pi R\rho $ $ \Rightarrow \,\frac{{{g_1}}}{{{g_2}}} = \frac{{{\rho _1}{R_1}}}{{{\rho _2}{R_2}}}$ $ = \frac{1}{2} \times \frac{4}{1} = \frac{2}{1}$